Base | Representation |
---|---|
bin | 110100111000000110… |
… | …0011000100010000111 |
3 | 101212002121002000210212 |
4 | 1221300030120202013 |
5 | 3330023132202403 |
6 | 124055333310035 |
7 | 11126624230616 |
oct | 1516014304207 |
9 | 355077060725 |
10 | 113551444103 |
11 | 4417a914689 |
12 | 1a01019531b |
13 | a928209016 |
14 | 56d2b3387d |
15 | 2e48cb74d8 |
hex | 1a70318887 |
113551444103 has 2 divisors, whose sum is σ = 113551444104. Its totient is φ = 113551444102.
The previous prime is 113551444007. The next prime is 113551444129. The reversal of 113551444103 is 301444155311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113551444103 - 218 = 113551181959 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 113551444103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113551444603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56775722051 + 56775722052.
It is an arithmetic number, because the mean of its divisors is an integer number (56775722052).
Almost surely, 2113551444103 is an apocalyptic number.
113551444103 is a deficient number, since it is larger than the sum of its proper divisors (1).
113551444103 is an equidigital number, since it uses as much as digits as its factorization.
113551444103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 113551444103 its reverse (301444155311), we get a palindrome (414995599414).
The spelling of 113551444103 in words is "one hundred thirteen billion, five hundred fifty-one million, four hundred forty-four thousand, one hundred three".
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