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113553011351513 is a prime number
BaseRepresentation
bin11001110100011010011110…
…111001111001111111011001
3112220001120011121020110010002
4121310122132321321333121
5104340423031401222023
61041301311103502345
732626635322640456
oct3164323671717731
9486046147213102
10113553011351513
11331aa61a650378
121089b4018b79b5
134b49006849136
142007dd06aa82d
15d1db939b6b28
hex67469ee79fd9

113553011351513 has 2 divisors, whose sum is σ = 113553011351514. Its totient is φ = 113553011351512.

The previous prime is 113553011351509. The next prime is 113553011351551. The reversal of 113553011351513 is 315153110355311.

It is an a-pointer prime, because the next prime (113553011351551) can be obtained adding 113553011351513 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 58109320964809 + 55443690386704 = 7622947^2 + 7446052^2 .

It is a cyclic number.

It is not a de Polignac number, because 113553011351513 - 22 = 113553011351509 is a prime.

It is not a weakly prime, because it can be changed into another prime (113553011351573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56776505675756 + 56776505675757.

It is an arithmetic number, because the mean of its divisors is an integer number (56776505675757).

Almost surely, 2113553011351513 is an apocalyptic number.

It is an amenable number.

113553011351513 is a deficient number, since it is larger than the sum of its proper divisors (1).

113553011351513 is an equidigital number, since it uses as much as digits as its factorization.

113553011351513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50625, while the sum is 38.

The spelling of 113553011351513 in words is "one hundred thirteen trillion, five hundred fifty-three billion, eleven million, three hundred fifty-one thousand, five hundred thirteen".