Base | Representation |
---|---|
bin | 10101001001110011… |
… | …10110111000111101 |
3 | 1002022110101021112111 |
4 | 22210321312320331 |
5 | 141224240040203 |
6 | 5114522334021 |
7 | 551266132051 |
oct | 124471667075 |
9 | 32273337474 |
10 | 11356565053 |
11 | 48a8537459 |
12 | 224b35a311 |
13 | 10bca6baa2 |
14 | 79a3a9c61 |
15 | 46702326d |
hex | 2a4e76e3d |
11356565053 has 2 divisors, whose sum is σ = 11356565054. Its totient is φ = 11356565052.
The previous prime is 11356564997. The next prime is 11356565071. The reversal of 11356565053 is 35056565311.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8295930724 + 3060634329 = 91082^2 + 55323^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11356565053 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11356564997 and 11356565015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11356565083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5678282526 + 5678282527.
It is an arithmetic number, because the mean of its divisors is an integer number (5678282527).
Almost surely, 211356565053 is an apocalyptic number.
It is an amenable number.
11356565053 is a deficient number, since it is larger than the sum of its proper divisors (1).
11356565053 is an equidigital number, since it uses as much as digits as its factorization.
11356565053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 202500, while the sum is 40.
The spelling of 11356565053 in words is "eleven billion, three hundred fifty-six million, five hundred sixty-five thousand, fifty-three".
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