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113613499957 is a prime number
BaseRepresentation
bin110100111001111100…
…1000110111000110101
3101212020220211210102211
41221303321012320311
53330140023444312
6124105431333421
711131306546516
oct1516371067065
9355226753384
10113613499957
114420194a111
121a028b21271
13a938025969
1456db088a0d
152e4e4743a7
hex1a73e46e35

113613499957 has 2 divisors, whose sum is σ = 113613499958. Its totient is φ = 113613499956.

The previous prime is 113613499933. The next prime is 113613499981. The reversal of 113613499957 is 759994316311.

It is a balanced prime because it is at equal distance from previous prime (113613499933) and next prime (113613499981).

It can be written as a sum of positive squares in only one way, i.e., 109954580836 + 3658919121 = 331594^2 + 60489^2 .

It is an emirp because it is prime and its reverse (759994316311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113613499957 - 215 = 113613467189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113613499907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56806749978 + 56806749979.

It is an arithmetic number, because the mean of its divisors is an integer number (56806749979).

Almost surely, 2113613499957 is an apocalyptic number.

It is an amenable number.

113613499957 is a deficient number, since it is larger than the sum of its proper divisors (1).

113613499957 is an equidigital number, since it uses as much as digits as its factorization.

113613499957 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5511240, while the sum is 58.

The spelling of 113613499957 in words is "one hundred thirteen billion, six hundred thirteen million, four hundred ninety-nine thousand, nine hundred fifty-seven".