Base | Representation |
---|---|
bin | 110100111111110100… |
… | …0101001000010101101 |
3 | 101212202122112221101222 |
4 | 1221333220221002231 |
5 | 3331040442304442 |
6 | 124141150113125 |
7 | 11136221242022 |
oct | 1517750510255 |
9 | 355678487358 |
10 | 113810509997 |
11 | 442a307a728 |
12 | 1a082aab7a5 |
13 | a969aa4052 |
14 | 57192cd549 |
15 | 2e618dc8d2 |
hex | 1a7fa290ad |
113810509997 has 2 divisors, whose sum is σ = 113810509998. Its totient is φ = 113810509996.
The previous prime is 113810509951. The next prime is 113810510003. The reversal of 113810509997 is 799905018311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 83434900201 + 30375609796 = 288851^2 + 174286^2 .
It is a cyclic number.
It is not a de Polignac number, because 113810509997 - 212 = 113810505901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113810500997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56905254998 + 56905254999.
It is an arithmetic number, because the mean of its divisors is an integer number (56905254999).
Almost surely, 2113810509997 is an apocalyptic number.
It is an amenable number.
113810509997 is a deficient number, since it is larger than the sum of its proper divisors (1).
113810509997 is an equidigital number, since it uses as much as digits as its factorization.
113810509997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 612360, while the sum is 53.
The spelling of 113810509997 in words is "one hundred thirteen billion, eight hundred ten million, five hundred nine thousand, nine hundred ninety-seven".
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