Base | Representation |
---|---|
bin | 10101001101001101… |
… | …01001101101000111 |
3 | 1002101110001020012022 |
4 | 22212212221231013 |
5 | 141304040202433 |
6 | 5121421513355 |
7 | 552063423614 |
oct | 124646515507 |
9 | 32343036168 |
10 | 11385084743 |
11 | 491264674a |
12 | 2258a1285b |
13 | 10c5946046 |
14 | 7a00b150b |
15 | 4697a8698 |
hex | 2a69a9b47 |
11385084743 has 2 divisors, whose sum is σ = 11385084744. Its totient is φ = 11385084742.
The previous prime is 11385084721. The next prime is 11385084787. The reversal of 11385084743 is 34748058311.
It is an a-pointer prime, because the next prime (11385084787) can be obtained adding 11385084743 to its sum of digits (44).
It is a weak prime.
It is an emirp because it is prime and its reverse (34748058311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11385084743 - 222 = 11380890439 is a prime.
It is a super-3 number, since 3×113850847433 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11385084694 and 11385084703.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11385084343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5692542371 + 5692542372.
It is an arithmetic number, because the mean of its divisors is an integer number (5692542372).
Almost surely, 211385084743 is an apocalyptic number.
11385084743 is a deficient number, since it is larger than the sum of its proper divisors (1).
11385084743 is an equidigital number, since it uses as much as digits as its factorization.
11385084743 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 322560, while the sum is 44.
The spelling of 11385084743 in words is "eleven billion, three hundred eighty-five million, eighty-four thousand, seven hundred forty-three".
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