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114000040310413 is a prime number
BaseRepresentation
bin11001111010111010110011…
…111010000011011010001101
3112221122022000211002110112111
4121322322303322003122031
5104420234040304413123
61042242521233504021
733004142162253025
oct3172726372033215
9487568024073474
10114000040310413
1133362166864654
1210951b7aa12011
134b7c208541aba
1420218ba774a85
15d2a608ed190d
hex67aeb3e8368d

114000040310413 has 2 divisors, whose sum is σ = 114000040310414. Its totient is φ = 114000040310412.

The previous prime is 114000040310369. The next prime is 114000040310557. The reversal of 114000040310413 is 314013040000411.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108142154336164 + 5857885974249 = 10399142^2 + 2420307^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114000040310413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114000040310213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57000020155206 + 57000020155207.

It is an arithmetic number, because the mean of its divisors is an integer number (57000020155207).

Almost surely, 2114000040310413 is an apocalyptic number.

It is an amenable number.

114000040310413 is a deficient number, since it is larger than the sum of its proper divisors (1).

114000040310413 is an equidigital number, since it uses as much as digits as its factorization.

114000040310413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 114000040310413 its reverse (314013040000411), we get a palindrome (428013080310824).

The spelling of 114000040310413 in words is "one hundred fourteen trillion, forty million, three hundred ten thousand, four hundred thirteen".