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114003111031531 is a prime number
BaseRepresentation
bin11001111010111101101010…
…111011111011001011101011
3112221122120221211012021000021
4121322331222323323023223
5104420311332411002111
61042244150050021311
733004311240044521
oct3172755273731353
9487576854167007
10114003111031531
11333634a21388a7
1210952697277837
134b7c5a7788147
142021acc50a311
15d2a738894d71
hex67af6aefb2eb

114003111031531 has 2 divisors, whose sum is σ = 114003111031532. Its totient is φ = 114003111031530.

The previous prime is 114003111031529. The next prime is 114003111031541. The reversal of 114003111031531 is 135130111300411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114003111031531 - 21 = 114003111031529 is a prime.

It is a super-2 number, since 2×1140031110315312 (a number of 29 digits) contains 22 as substring.

Together with 114003111031529, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 114003111031496 and 114003111031505.

It is not a weakly prime, because it can be changed into another prime (114003111031501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57001555515765 + 57001555515766.

It is an arithmetic number, because the mean of its divisors is an integer number (57001555515766).

Almost surely, 2114003111031531 is an apocalyptic number.

114003111031531 is a deficient number, since it is larger than the sum of its proper divisors (1).

114003111031531 is an equidigital number, since it uses as much as digits as its factorization.

114003111031531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 25.

Adding to 114003111031531 its reverse (135130111300411), we get a palindrome (249133222331942).

The spelling of 114003111031531 in words is "one hundred fourteen trillion, three billion, one hundred eleven million, thirty-one thousand, five hundred thirty-one".