Base | Representation |
---|---|
bin | 11001111011000100010011… |
… | …110111101000110010010111 |
3 | 112221200021100200000210002212 |
4 | 121323010103313220302113 |
5 | 104420420432444140112 |
6 | 1042251325321224035 |
7 | 33004653015143432 |
oct | 3173042367506227 |
9 | 487607320023085 |
10 | 114010240224407 |
11 | 33366520402a3a |
12 | 10953b4693201b |
13 | 4b80172786377 |
14 | 20221a7296819 |
15 | d2aa046cd522 |
hex | 67b113de8c97 |
114010240224407 has 2 divisors, whose sum is σ = 114010240224408. Its totient is φ = 114010240224406.
The previous prime is 114010240224319. The next prime is 114010240224443. The reversal of 114010240224407 is 704422042010411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114010240224407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114010240224497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57005120112203 + 57005120112204.
It is an arithmetic number, because the mean of its divisors is an integer number (57005120112204).
Almost surely, 2114010240224407 is an apocalyptic number.
114010240224407 is a deficient number, since it is larger than the sum of its proper divisors (1).
114010240224407 is an equidigital number, since it uses as much as digits as its factorization.
114010240224407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14336, while the sum is 32.
Adding to 114010240224407 its reverse (704422042010411), we get a palindrome (818432282234818).
The spelling of 114010240224407 in words is "one hundred fourteen trillion, ten billion, two hundred forty million, two hundred twenty-four thousand, four hundred seven".
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