11401113301 has 2 divisors, whose sum is σ = 11401113302. Its totient is φ = 11401113300.

The previous prime is 11401113299. The next prime is 11401113337. The reversal of 11401113301 is 10331110411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11336712676 + 64400625 = 106474^2 + 8025^2 .

It is an emirp because it is prime and its reverse (10331110411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11401113301 - 2¹ = 11401113299 is a prime.

Together with 11401113299, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11401113601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700556650 + 5700556651.

It is an arithmetic number, because the mean of its divisors is an integer number (5700556651).

Almost surely, 2^11401113301 is an apocalyptic number.

It is an amenable number.

11401113301 is a deficient number, since it is larger than the sum of its proper divisors (1).

11401113301 is an equidigital number, since it uses as much as digits as its factorization.

11401113301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 11401113301 its reverse (10331110411), we get a palindrome (21732223712).

The spelling of 11401113301 in words is "eleven billion, four hundred one million, one hundred thirteen thousand, three hundred one".