Base | Representation |
---|---|
bin | 10101001111000111… |
… | …10011001010111101 |
3 | 1002102120012121121122 |
4 | 22213203303022331 |
5 | 141322141124201 |
6 | 5123153240325 |
7 | 552346605203 |
oct | 124743631275 |
9 | 32376177548 |
10 | 11401114301 |
11 | 49206a4a15 |
12 | 22622630a5 |
13 | 10c90691a5 |
14 | 7a2285073 |
15 | 46adc2e1b |
hex | 2a78f32bd |
11401114301 has 2 divisors, whose sum is σ = 11401114302. Its totient is φ = 11401114300.
The previous prime is 11401114297. The next prime is 11401114339. The reversal of 11401114301 is 10341110411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9511125625 + 1889988676 = 97525^2 + 43474^2 .
It is a cyclic number.
It is not a de Polignac number, because 11401114301 - 22 = 11401114297 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11401114301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11401113301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700557150 + 5700557151.
It is an arithmetic number, because the mean of its divisors is an integer number (5700557151).
Almost surely, 211401114301 is an apocalyptic number.
It is an amenable number.
11401114301 is a deficient number, since it is larger than the sum of its proper divisors (1).
11401114301 is an equidigital number, since it uses as much as digits as its factorization.
11401114301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 11401114301 its reverse (10341110411), we get a palindrome (21742224712).
The spelling of 11401114301 in words is "eleven billion, four hundred one million, one hundred fourteen thousand, three hundred one".
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