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114011341441 is a prime number
BaseRepresentation
bin110101000101110011…
…0110000001010000001
3101220021122110020100121
41222023212300022001
53331443400411231
6124213122420241
711144210261314
oct1521346601201
9356248406317
10114011341441
1144396480328
121a11a201681
13a99c58c91a
145737c4a97b
152e7435d311
hex1a8b9b0281

114011341441 has 2 divisors, whose sum is σ = 114011341442. Its totient is φ = 114011341440.

The previous prime is 114011341397. The next prime is 114011341487. The reversal of 114011341441 is 144143110411.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111425110416 + 2586231025 = 333804^2 + 50855^2 .

It is a cyclic number.

It is not a de Polignac number, because 114011341441 - 225 = 113977787009 is a prime.

It is not a weakly prime, because it can be changed into another prime (114011348441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57005670720 + 57005670721.

It is an arithmetic number, because the mean of its divisors is an integer number (57005670721).

Almost surely, 2114011341441 is an apocalyptic number.

It is an amenable number.

114011341441 is a deficient number, since it is larger than the sum of its proper divisors (1).

114011341441 is an equidigital number, since it uses as much as digits as its factorization.

114011341441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 114011341441 its reverse (144143110411), we get a palindrome (258154451852).

The spelling of 114011341441 in words is "one hundred fourteen billion, eleven million, three hundred forty-one thousand, four hundred forty-one".