Base | Representation |
---|---|
bin | 110101000101110011… |
… | …0110000001010000001 |
3 | 101220021122110020100121 |
4 | 1222023212300022001 |
5 | 3331443400411231 |
6 | 124213122420241 |
7 | 11144210261314 |
oct | 1521346601201 |
9 | 356248406317 |
10 | 114011341441 |
11 | 44396480328 |
12 | 1a11a201681 |
13 | a99c58c91a |
14 | 5737c4a97b |
15 | 2e7435d311 |
hex | 1a8b9b0281 |
114011341441 has 2 divisors, whose sum is σ = 114011341442. Its totient is φ = 114011341440.
The previous prime is 114011341397. The next prime is 114011341487. The reversal of 114011341441 is 144143110411.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111425110416 + 2586231025 = 333804^2 + 50855^2 .
It is a cyclic number.
It is not a de Polignac number, because 114011341441 - 225 = 113977787009 is a prime.
It is not a weakly prime, because it can be changed into another prime (114011348441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57005670720 + 57005670721.
It is an arithmetic number, because the mean of its divisors is an integer number (57005670721).
Almost surely, 2114011341441 is an apocalyptic number.
It is an amenable number.
114011341441 is a deficient number, since it is larger than the sum of its proper divisors (1).
114011341441 is an equidigital number, since it uses as much as digits as its factorization.
114011341441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 114011341441 its reverse (144143110411), we get a palindrome (258154451852).
The spelling of 114011341441 in words is "one hundred fourteen billion, eleven million, three hundred forty-one thousand, four hundred forty-one".
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