Base | Representation |
---|---|
bin | 11001111011000110011010… |
… | …101100000111110110011101 |
3 | 112221200111012022012111100221 |
4 | 121323012122230013312131 |
5 | 104420440101021130302 |
6 | 1042252342001521341 |
7 | 33005063042054545 |
oct | 3173063254076635 |
9 | 487614168174327 |
10 | 114012502130077 |
11 | 33367481175171 |
12 | 10954478343251 |
13 | 4b804432811a5 |
14 | 202233d84a325 |
15 | d2aad8077937 |
hex | 67b19ab07d9d |
114012502130077 has 2 divisors, whose sum is σ = 114012502130078. Its totient is φ = 114012502130076.
The previous prime is 114012502130011. The next prime is 114012502130099. The reversal of 114012502130077 is 770031205210411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 85849749684196 + 28162752445881 = 9265514^2 + 5306859^2 .
It is a cyclic number.
It is not a de Polignac number, because 114012502130077 - 215 = 114012502097309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114016502130077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57006251065038 + 57006251065039.
It is an arithmetic number, because the mean of its divisors is an integer number (57006251065039).
Almost surely, 2114012502130077 is an apocalyptic number.
It is an amenable number.
114012502130077 is a deficient number, since it is larger than the sum of its proper divisors (1).
114012502130077 is an equidigital number, since it uses as much as digits as its factorization.
114012502130077 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11760, while the sum is 34.
Adding to 114012502130077 its reverse (770031205210411), we get a palindrome (884043707340488).
The spelling of 114012502130077 in words is "one hundred fourteen trillion, twelve billion, five hundred two million, one hundred thirty thousand, seventy-seven".
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