Base | Representation |
---|---|
bin | 11001111011000111110101… |
… | …010011001110101110000111 |
3 | 112221200122010020201201100212 |
4 | 121323013311103032232013 |
5 | 104421001204204100041 |
6 | 1042253152505030035 |
7 | 33005145521420156 |
oct | 3173076523165607 |
9 | 487618106651325 |
10 | 114014022331271 |
11 | 333680912a2897 |
12 | 1095482148531b |
13 | 4b806261c731a |
14 | 20224456cb59d |
15 | d2ab767628eb |
hex | 67b1f54ceb87 |
114014022331271 has 2 divisors, whose sum is σ = 114014022331272. Its totient is φ = 114014022331270.
The previous prime is 114014022331171. The next prime is 114014022331277. The reversal of 114014022331271 is 172133220410411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114014022331271 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114014022331277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57007011165635 + 57007011165636.
It is an arithmetic number, because the mean of its divisors is an integer number (57007011165636).
Almost surely, 2114014022331271 is an apocalyptic number.
114014022331271 is a deficient number, since it is larger than the sum of its proper divisors (1).
114014022331271 is an equidigital number, since it uses as much as digits as its factorization.
114014022331271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 114014022331271 its reverse (172133220410411), we get a palindrome (286147242741682).
The spelling of 114014022331271 in words is "one hundred fourteen trillion, fourteen billion, twenty-two million, three hundred thirty-one thousand, two hundred seventy-one".
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