114014144301341 has 2 divisors, whose sum is σ = 114014144301342. Its totient is φ = 114014144301340.

The previous prime is 114014144301293. The next prime is 114014144301383. The reversal of 114014144301341 is 143103441410411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77492016732025 + 36522127569316 = 8802955^2 + 6043354^2 .

It is an emirp because it is prime and its reverse (143103441410411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114014144301341 is a prime.

It is a super-3 number, since 3×114014144301341³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114014144301298 and 114014144301307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114014144301391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57007072150670 + 57007072150671.

It is an arithmetic number, because the mean of its divisors is an integer number (57007072150671).

Almost surely, 2^{114014144301341} is an apocalyptic number.

It is an amenable number.

114014144301341 is a deficient number, since it is larger than the sum of its proper divisors (1).

114014144301341 is an equidigital number, since it uses as much as digits as its factorization.

114014144301341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216, while the sum is 32.

Adding to 114014144301341 its reverse (143103441410411), we get a palindrome (257117585711752).

The spelling of 114014144301341 in words is "one hundred fourteen trillion, fourteen billion, one hundred forty-four million, three hundred one thousand, three hundred forty-one".