Base | Representation |
---|---|
bin | 10101001111001011… |
… | …10110111110000111 |
3 | 1002102121020001011002 |
4 | 22213211312332013 |
5 | 141322310413101 |
6 | 5123213003515 |
7 | 552354314126 |
oct | 124745667607 |
9 | 32377201132 |
10 | 11401654151 |
11 | 4920a33578 |
12 | 226248359b |
13 | 10c91c7b24 |
14 | 7a2385abd |
15 | 46ae7cd6b |
hex | 2a7976f87 |
11401654151 has 2 divisors, whose sum is σ = 11401654152. Its totient is φ = 11401654150.
The previous prime is 11401654109. The next prime is 11401654153. The reversal of 11401654151 is 15145610411.
It is a strong prime.
It is an emirp because it is prime and its reverse (15145610411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11401654151 - 218 = 11401392007 is a prime.
It is a Sophie Germain prime.
Together with 11401654153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11401654153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700827075 + 5700827076.
It is an arithmetic number, because the mean of its divisors is an integer number (5700827076).
Almost surely, 211401654151 is an apocalyptic number.
11401654151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11401654151 is an equidigital number, since it uses as much as digits as its factorization.
11401654151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2400, while the sum is 29.
The spelling of 11401654151 in words is "eleven billion, four hundred one million, six hundred fifty-four thousand, one hundred fifty-one".
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