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11402030114053 is a prime number
BaseRepresentation
bin1010010111101011110111…
…1101000110010100000101
31111101000122002020112020121
42211322331331012110011
52443302324202122203
640130004220101541
72254524635601235
oct245727575062405
944330562215217
1011402030114053
1136a6634827017
1213419589948b1
1364928c5215c7
142b5c0b1d1cc5
1514b8d64130bd
hexa5ebdf46505

11402030114053 has 2 divisors, whose sum is σ = 11402030114054. Its totient is φ = 11402030114052.

The previous prime is 11402030113993. The next prime is 11402030114087. The reversal of 11402030114053 is 35041103020411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10689022131649 + 713007982404 = 3269407^2 + 844398^2 .

It is a cyclic number.

It is not a de Polignac number, because 11402030114053 - 29 = 11402030113541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11402030114353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701015057026 + 5701015057027.

It is an arithmetic number, because the mean of its divisors is an integer number (5701015057027).

Almost surely, 211402030114053 is an apocalyptic number.

It is an amenable number.

11402030114053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11402030114053 is an equidigital number, since it uses as much as digits as its factorization.

11402030114053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 11402030114053 its reverse (35041103020411), we get a palindrome (46443133134464).

The spelling of 11402030114053 in words is "eleven trillion, four hundred two billion, thirty million, one hundred fourteen thousand, fifty-three".