Base | Representation |
---|---|
bin | 1010010111101011110111… |
… | …1101000110010100000101 |
3 | 1111101000122002020112020121 |
4 | 2211322331331012110011 |
5 | 2443302324202122203 |
6 | 40130004220101541 |
7 | 2254524635601235 |
oct | 245727575062405 |
9 | 44330562215217 |
10 | 11402030114053 |
11 | 36a6634827017 |
12 | 13419589948b1 |
13 | 64928c5215c7 |
14 | 2b5c0b1d1cc5 |
15 | 14b8d64130bd |
hex | a5ebdf46505 |
11402030114053 has 2 divisors, whose sum is σ = 11402030114054. Its totient is φ = 11402030114052.
The previous prime is 11402030113993. The next prime is 11402030114087. The reversal of 11402030114053 is 35041103020411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10689022131649 + 713007982404 = 3269407^2 + 844398^2 .
It is a cyclic number.
It is not a de Polignac number, because 11402030114053 - 29 = 11402030113541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11402030114353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701015057026 + 5701015057027.
It is an arithmetic number, because the mean of its divisors is an integer number (5701015057027).
Almost surely, 211402030114053 is an apocalyptic number.
It is an amenable number.
11402030114053 is a deficient number, since it is larger than the sum of its proper divisors (1).
11402030114053 is an equidigital number, since it uses as much as digits as its factorization.
11402030114053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 11402030114053 its reverse (35041103020411), we get a palindrome (46443133134464).
The spelling of 11402030114053 in words is "eleven trillion, four hundred two billion, thirty million, one hundred fourteen thousand, fifty-three".
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