Base | Representation |
---|---|
bin | 1010010111101100001010… |
… | …1111100010001001001111 |
3 | 1111101000211200101201100221 |
4 | 2211323002233202021033 |
5 | 2443303010233202421 |
6 | 40130020205532211 |
7 | 2254526632440532 |
oct | 245730257421117 |
9 | 44330750351327 |
10 | 11402110444111 |
11 | 36a66761031a2 |
12 | 134197b874067 |
13 | 6492a3068c9a |
14 | 2b5c17b42a19 |
15 | 14b8dd4ce841 |
hex | a5ec2be224f |
11402110444111 has 2 divisors, whose sum is σ = 11402110444112. Its totient is φ = 11402110444110.
The previous prime is 11402110444051. The next prime is 11402110444163. The reversal of 11402110444111 is 11144401120411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11402110444111 - 233 = 11393520509519 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11402110444811) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701055222055 + 5701055222056.
It is an arithmetic number, because the mean of its divisors is an integer number (5701055222056).
Almost surely, 211402110444111 is an apocalyptic number.
11402110444111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11402110444111 is an equidigital number, since it uses as much as digits as its factorization.
11402110444111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 512, while the sum is 25.
Adding to 11402110444111 its reverse (11144401120411), we get a palindrome (22546511564522).
The spelling of 11402110444111 in words is "eleven trillion, four hundred two billion, one hundred ten million, four hundred forty-four thousand, one hundred eleven".
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