Base | Representation |
---|---|
bin | 10000100101111111001… |
… | …111001011101101010011 |
3 | 11001000022112112201000122 |
4 | 100211333033023231103 |
5 | 122140314030114422 |
6 | 2231502544140455 |
7 | 145245502513433 |
oct | 20457717135523 |
9 | 4030275481018 |
10 | 1140301019987 |
11 | 3aa66521a888 |
12 | 164bb860772b |
13 | 836b732496c |
14 | 3d295a322c3 |
15 | 1e9ddae8d42 |
hex | 1097f3cbb53 |
1140301019987 has 2 divisors, whose sum is σ = 1140301019988. Its totient is φ = 1140301019986.
The previous prime is 1140301019971. The next prime is 1140301020031. The reversal of 1140301019987 is 7899101030411.
It is an a-pointer prime, because the next prime (1140301020031) can be obtained adding 1140301019987 to its sum of digits (44).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1140301019987 - 24 = 1140301019971 is a prime.
It is not a weakly prime, because it can be changed into another prime (1140301019917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570150509993 + 570150509994.
It is an arithmetic number, because the mean of its divisors is an integer number (570150509994).
Almost surely, 21140301019987 is an apocalyptic number.
1140301019987 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140301019987 is an equidigital number, since it uses as much as digits as its factorization.
1140301019987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 44.
The spelling of 1140301019987 in words is "one trillion, one hundred forty billion, three hundred one million, nineteen thousand, nine hundred eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •