Base | Representation |
---|---|
bin | 10000100101111111001… |
… | …111001011101101111111 |
3 | 11001000022112112201002021 |
4 | 100211333033023231333 |
5 | 122140314030120111 |
6 | 2231502544141011 |
7 | 145245502513525 |
oct | 20457717135577 |
9 | 4030275481067 |
10 | 1140301020031 |
11 | 3aa66521a918 |
12 | 164bb8607767 |
13 | 836b73249a4 |
14 | 3d295a32315 |
15 | 1e9ddae8d71 |
hex | 1097f3cbb7f |
1140301020031 has 2 divisors, whose sum is σ = 1140301020032. Its totient is φ = 1140301020030.
The previous prime is 1140301019987. The next prime is 1140301020071. The reversal of 1140301020031 is 1300201030411.
It is a strong prime.
It is an emirp because it is prime and its reverse (1300201030411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1140301020031 - 211 = 1140301017983 is a prime.
It is a super-2 number, since 2×11403010200312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1140301019987 and 1140301020014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1140301020071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570150510015 + 570150510016.
It is an arithmetic number, because the mean of its divisors is an integer number (570150510016).
Almost surely, 21140301020031 is an apocalyptic number.
1140301020031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140301020031 is an equidigital number, since it uses as much as digits as its factorization.
1140301020031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1140301020031 its reverse (1300201030411), we get a palindrome (2440502050442).
The spelling of 1140301020031 in words is "one trillion, one hundred forty billion, three hundred one million, twenty thousand, thirty-one".
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