Base | Representation |
---|---|
bin | 10000100101111111111… |
… | …101010100010101101111 |
3 | 11001000100101022010211211 |
4 | 100211333331110111233 |
5 | 122140330124121332 |
6 | 2231504055255251 |
7 | 145246010354026 |
oct | 20457775242557 |
9 | 4030311263754 |
10 | 1140313113967 |
11 | 3aa671030205 |
12 | 16500067a527 |
13 | 836b999a671 |
14 | 3d29749d8bd |
15 | 1e9debd7447 |
hex | 1097ff5456f |
1140313113967 has 2 divisors, whose sum is σ = 1140313113968. Its totient is φ = 1140313113966.
The previous prime is 1140313113941. The next prime is 1140313114007. The reversal of 1140313113967 is 7693113130411.
It is an a-pointer prime, because the next prime (1140313114007) can be obtained adding 1140313113967 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1140313113967 - 223 = 1140304725359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1140313113917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570156556983 + 570156556984.
It is an arithmetic number, because the mean of its divisors is an integer number (570156556984).
Almost surely, 21140313113967 is an apocalyptic number.
1140313113967 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140313113967 is an equidigital number, since it uses as much as digits as its factorization.
1140313113967 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40824, while the sum is 40.
The spelling of 1140313113967 in words is "one trillion, one hundred forty billion, three hundred thirteen million, one hundred thirteen thousand, nine hundred sixty-seven".
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