Base | Representation |
---|---|
bin | 11001111011011001100001… |
… | …001011100100010011101111 |
3 | 112221202110010200101111102210 |
4 | 121323121201023210103233 |
5 | 104421304102101143210 |
6 | 1042310013110221503 |
7 | 33006420226151013 |
oct | 3173314113442357 |
9 | 487673120344383 |
10 | 114033012131055 |
11 | 333751465714a6 |
12 | 10958441054893 |
13 | 4b82361503044 |
14 | 202332776c543 |
15 | d2b3d8984e20 |
hex | 67b6612e44ef |
114033012131055 has 64 divisors (see below), whose sum is σ = 183674799576576. Its totient is φ = 60411355200000.
The previous prime is 114033012131023. The next prime is 114033012131069. The reversal of 114033012131055 is 550131210330411.
It is not a de Polignac number, because 114033012131055 - 25 = 114033012131023 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5034336480 + ... + 5034359130.
It is an arithmetic number, because the mean of its divisors is an integer number (2869918743384).
Almost surely, 2114033012131055 is an apocalyptic number.
114033012131055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114033012131055 is a deficient number, since it is larger than the sum of its proper divisors (69641787445521).
114033012131055 is a wasteful number, since it uses less digits than its factorization.
114033012131055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25528.
The product of its (nonzero) digits is 5400, while the sum is 30.
Adding to 114033012131055 its reverse (550131210330411), we get a palindrome (664164222461466).
The spelling of 114033012131055 in words is "one hundred fourteen trillion, thirty-three billion, twelve million, one hundred thirty-one thousand, fifty-five".
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