Base | Representation |
---|---|
bin | 110101000110011101… |
… | …0001110101011011101 |
3 | 101220100011122000011001 |
4 | 1222030322032223131 |
5 | 3332020001140123 |
6 | 124215223430301 |
7 | 11144564262133 |
oct | 1521472165335 |
9 | 356304560131 |
10 | 114033224413 |
11 | 443a7867329 |
12 | 1a1255b5391 |
13 | a9a3c82124 |
14 | 573ab05753 |
15 | 2e762320ad |
hex | 1a8ce8eadd |
114033224413 has 2 divisors, whose sum is σ = 114033224414. Its totient is φ = 114033224412.
The previous prime is 114033224387. The next prime is 114033224497. The reversal of 114033224413 is 314422330411.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111795272164 + 2237952249 = 334358^2 + 47307^2 .
It is a cyclic number.
It is not a de Polignac number, because 114033224413 - 29 = 114033223901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114033224113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57016612206 + 57016612207.
It is an arithmetic number, because the mean of its divisors is an integer number (57016612207).
Almost surely, 2114033224413 is an apocalyptic number.
It is an amenable number.
114033224413 is a deficient number, since it is larger than the sum of its proper divisors (1).
114033224413 is an equidigital number, since it uses as much as digits as its factorization.
114033224413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 114033224413 its reverse (314422330411), we get a palindrome (428455554824).
The spelling of 114033224413 in words is "one hundred fourteen billion, thirty-three million, two hundred twenty-four thousand, four hundred thirteen".
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