Base | Representation |
---|---|
bin | 110101000110011110… |
… | …1111111101000001101 |
3 | 101220100020111010221221 |
4 | 1222030331333220031 |
5 | 3332020224230331 |
6 | 124215300523341 |
7 | 11144605542361 |
oct | 1521475775015 |
9 | 356306433857 |
10 | 114034211341 |
11 | 443a8380876 |
12 | 1a1259b0551 |
13 | a9a42393cb |
14 | 573acc12a1 |
15 | 2e76379711 |
hex | 1a8cf7fa0d |
114034211341 has 2 divisors, whose sum is σ = 114034211342. Its totient is φ = 114034211340.
The previous prime is 114034211323. The next prime is 114034211371. The reversal of 114034211341 is 143112430411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 61526322025 + 52507889316 = 248045^2 + 229146^2 .
It is a cyclic number.
It is not a de Polignac number, because 114034211341 - 211 = 114034209293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114034211371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57017105670 + 57017105671.
It is an arithmetic number, because the mean of its divisors is an integer number (57017105671).
Almost surely, 2114034211341 is an apocalyptic number.
It is an amenable number.
114034211341 is a deficient number, since it is larger than the sum of its proper divisors (1).
114034211341 is an equidigital number, since it uses as much as digits as its factorization.
114034211341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 114034211341 its reverse (143112430411), we get a palindrome (257146641752).
The spelling of 114034211341 in words is "one hundred fourteen billion, thirty-four million, two hundred eleven thousand, three hundred forty-one".
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