1140400401431 has 2 divisors, whose sum is σ = 1140400401432. Its totient is φ = 1140400401430.

The previous prime is 1140400401407. The next prime is 1140400401433. The reversal of 1140400401431 is 1341040040411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1140400401431 - 2¹⁰ = 1140400400407 is a prime.

It is a super-2 number, since 2×1140400401431² (a number of 25 digits) contains 22 as substring.

Together with 1140400401433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1140400401397 and 1140400401406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1140400401433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570200200715 + 570200200716.

It is an arithmetic number, because the mean of its divisors is an integer number (570200200716).

Almost surely, 2^{1140400401431} is an apocalyptic number.

1140400401431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140400401431 is an equidigital number, since it uses as much as digits as its factorization.

1140400401431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1140400401431 its reverse (1341040040411), we get a palindrome (2481440441842).

The spelling of 1140400401431 in words is "one trillion, one hundred forty billion, four hundred million, four hundred one thousand, four hundred thirty-one".