Base | Representation |
---|---|
bin | 1010010111110100000010… |
… | …1010101101110010011111 |
3 | 1111101020021220202021112221 |
4 | 2211331000222231302133 |
5 | 2443321322104012203 |
6 | 40131005555410211 |
7 | 2254633165010302 |
oct | 245750052556237 |
9 | 44336256667487 |
10 | 11404223110303 |
11 | 36a755a702611 |
12 | 134226b2b3967 |
13 | 64954b97011a |
14 | 2b5d78568b39 |
15 | 14b9b3be9abd |
hex | a5f40aadc9f |
11404223110303 has 2 divisors, whose sum is σ = 11404223110304. Its totient is φ = 11404223110302.
The previous prime is 11404223110261. The next prime is 11404223110321. The reversal of 11404223110303 is 30301132240411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11404223110303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11404223150303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5702111555151 + 5702111555152.
It is an arithmetic number, because the mean of its divisors is an integer number (5702111555152).
Almost surely, 211404223110303 is an apocalyptic number.
11404223110303 is a deficient number, since it is larger than the sum of its proper divisors (1).
11404223110303 is an equidigital number, since it uses as much as digits as its factorization.
11404223110303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11404223110303 its reverse (30301132240411), we get a palindrome (41705355350714).
The spelling of 11404223110303 in words is "eleven trillion, four hundred four billion, two hundred twenty-three million, one hundred ten thousand, three hundred three".
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