Search a number
-
+
114043133000 = 2353613186041
BaseRepresentation
bin110101000110110000…
…0000001110001001000
3101220100212021102011202
41222031200001301020
53332030020224000
6124220220043332
711145044431136
oct1521540016110
9356325242152
10114043133000
1144402414845
121a128993548
13a9a60411b4
14573c164756
152e7703cdd5
hex1a8d801c48

114043133000 has 64 divisors (see below), whose sum is σ = 267297703920. Its totient is φ = 45542592000.

The previous prime is 114043132997. The next prime is 114043133003. The reversal of 114043133000 is 331340411.

114043133000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (114043132997) and next prime (114043133003).

It can be written as a sum of positive squares in 8 ways, for example, as 11754462724 + 102288670276 = 108418^2 + 319826^2 .

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (114043133003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 519980 + ... + 706020.

Almost surely, 2114043133000 is an apocalyptic number.

114043133000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 114043133000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (133648851960).

114043133000 is an abundant number, since it is smaller than the sum of its proper divisors (153254570920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

114043133000 is a wasteful number, since it uses less digits than its factorization.

114043133000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 186675 (or 186661 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 114043133000 its reverse (331340411), we get a palindrome (114374473411).

The spelling of 114043133000 in words is "one hundred fourteen billion, forty-three million, one hundred thirty-three thousand".

Divisors: 1 2 4 5 8 10 20 25 40 50 100 125 200 250 500 613 1000 1226 2452 3065 4904 6130 12260 15325 24520 30650 61300 76625 122600 153250 186041 306500 372082 613000 744164 930205 1488328 1860410 3720820 4651025 7441640 9302050 18604100 23255125 37208200 46510250 93020500 114043133 186041000 228086266 456172532 570215665 912345064 1140431330 2280862660 2851078325 4561725320 5702156650 11404313300 14255391625 22808626600 28510783250 57021566500 114043133000