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1140442124113 is a prime number
BaseRepresentation
bin10000100110000111101…
…001011100111101010001
311001000200101001112111101
4100212013221130331101
5122141111140432423
62231524544344401
7145252135052635
oct20460751347521
94030611045441
101140442124113
113aa727936466
12165037915101
138370a62a726
143d2aa682dc5
151e9eb1bc7ad
hex10987a5cf51

1140442124113 has 2 divisors, whose sum is σ = 1140442124114. Its totient is φ = 1140442124112.

The previous prime is 1140442124089. The next prime is 1140442124137. The reversal of 1140442124113 is 3114212440411.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (1140442124089) and next prime (1140442124137).

It can be written as a sum of positive squares in only one way, i.e., 1084780574784 + 55661549329 = 1041528^2 + 235927^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1140442124113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1140442127113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570221062056 + 570221062057.

It is an arithmetic number, because the mean of its divisors is an integer number (570221062057).

Almost surely, 21140442124113 is an apocalyptic number.

It is an amenable number.

1140442124113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140442124113 is an equidigital number, since it uses as much as digits as its factorization.

1140442124113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3072, while the sum is 28.

Adding to 1140442124113 its reverse (3114212440411), we get a palindrome (4254654564524).

The spelling of 1140442124113 in words is "one trillion, one hundred forty billion, four hundred forty-two million, one hundred twenty-four thousand, one hundred thirteen".