Base | Representation |
---|---|
bin | 11001111011100100000100… |
… | …100001000111100110101010 |
3 | 112221210112101022021212111001 |
4 | 121323210010201013212222 |
5 | 104422000303123321300 |
6 | 1042315125253225214 |
7 | 33010301055646216 |
oct | 3173440441074652 |
9 | 487715338255431 |
10 | 114044342401450 |
11 | 33379a3017932a |
12 | 1095a68363220a |
13 | 4b83448996556 |
14 | 2023ac0451946 |
15 | d2b84d51216a |
hex | 67b9048479aa |
114044342401450 has 24 divisors (see below), whose sum is σ = 212127096612960. Its totient is φ = 45616743466800.
The previous prime is 114044342401433. The next prime is 114044342401453. The reversal of 114044342401450 is 54104243440411.
It is a super-2 number, since 2×1140443424014502 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (114044342401453) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 22516416 + ... + 27112315.
It is an arithmetic number, because the mean of its divisors is an integer number (8838629025540).
Almost surely, 2114044342401450 is an apocalyptic number.
114044342401450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
114044342401450 is a deficient number, since it is larger than the sum of its proper divisors (98082754211510).
114044342401450 is a wasteful number, since it uses less digits than its factorization.
114044342401450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49674702 (or 49674697 counting only the distinct ones).
The product of its (nonzero) digits is 122880, while the sum is 37.
Adding to 114044342401450 its reverse (54104243440411), we get a palindrome (168148585841861).
The spelling of 114044342401450 in words is "one hundred fourteen trillion, forty-four billion, three hundred forty-two million, four hundred one thousand, four hundred fifty".
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