Base | Representation |
---|---|
bin | 10000100110101000111… |
… | …110100101100000111101 |
3 | 11001002010100021020111121 |
4 | 100212220332211200331 |
5 | 122143232313443232 |
6 | 2232100241550541 |
7 | 145302035063146 |
oct | 20465076454075 |
9 | 4032110236447 |
10 | 1141001312317 |
11 | 3aa994549879 |
12 | 165173045451 |
13 | 83799437119 |
14 | 3d320a44acd |
15 | 1ea30327d97 |
hex | 109a8fa583d |
1141001312317 has 2 divisors, whose sum is σ = 1141001312318. Its totient is φ = 1141001312316.
The previous prime is 1141001312309. The next prime is 1141001312327. The reversal of 1141001312317 is 7132131001411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 995387331481 + 145613980836 = 997691^2 + 381594^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141001312317 - 23 = 1141001312309 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1141001312291 and 1141001312300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1141001312327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570500656158 + 570500656159.
It is an arithmetic number, because the mean of its divisors is an integer number (570500656159).
Almost surely, 21141001312317 is an apocalyptic number.
It is an amenable number.
1141001312317 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141001312317 is an equidigital number, since it uses as much as digits as its factorization.
1141001312317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 1141001312317 its reverse (7132131001411), we get a palindrome (8273132313728).
The spelling of 1141001312317 in words is "one trillion, one hundred forty-one billion, one million, three hundred twelve thousand, three hundred seventeen".
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