Base | Representation |
---|---|
bin | 10000100110101001101… |
… | …000001100110010101111 |
3 | 11001002011002210110112201 |
4 | 100212221220030302233 |
5 | 122143243112033403 |
6 | 2232101311442331 |
7 | 145302226566166 |
oct | 20465150146257 |
9 | 4032132713481 |
10 | 1141012221103 |
11 | 3aa99a71a7a7 |
12 | 1651768263a7 |
13 | 8379b786521 |
14 | 3d3222843dd |
15 | 1ea3128021d |
hex | 109a9a0ccaf |
1141012221103 has 2 divisors, whose sum is σ = 1141012221104. Its totient is φ = 1141012221102.
The previous prime is 1141012221091. The next prime is 1141012221149. The reversal of 1141012221103 is 3011222101411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1141012221103 - 221 = 1141010123951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1141012221163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570506110551 + 570506110552.
It is an arithmetic number, because the mean of its divisors is an integer number (570506110552).
Almost surely, 21141012221103 is an apocalyptic number.
1141012221103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141012221103 is an equidigital number, since it uses as much as digits as its factorization.
1141012221103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 1141012221103 its reverse (3011222101411), we get a palindrome (4152234322514).
The spelling of 1141012221103 in words is "one trillion, one hundred forty-one billion, twelve million, two hundred twenty-one thousand, one hundred three".
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