Base | Representation |
---|---|
bin | 1010011000001011000011… |
… | …1111000000010001100111 |
3 | 1111101211020120020222100102 |
4 | 2212002300333000101213 |
5 | 2443422001011210031 |
6 | 40133511100134315 |
7 | 2255242260331466 |
oct | 246026077002147 |
9 | 44354216228312 |
10 | 11410402444391 |
11 | 36aa140790795 |
12 | 13434b483739b |
13 | 649cc4c38922 |
14 | 2b63a30da9dd |
15 | 14bc264587cb |
hex | a60b0fc0467 |
11410402444391 has 2 divisors, whose sum is σ = 11410402444392. Its totient is φ = 11410402444390.
The previous prime is 11410402444319. The next prime is 11410402444403. The reversal of 11410402444391 is 19344420401411.
Together with previous prime (11410402444319) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11410402444391 - 222 = 11410398250087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11410402434391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705201222195 + 5705201222196.
It is an arithmetic number, because the mean of its divisors is an integer number (5705201222196).
Almost surely, 211410402444391 is an apocalyptic number.
11410402444391 is a deficient number, since it is larger than the sum of its proper divisors (1).
11410402444391 is an equidigital number, since it uses as much as digits as its factorization.
11410402444391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 38.
The spelling of 11410402444391 in words is "eleven trillion, four hundred ten billion, four hundred two million, four hundred forty-four thousand, three hundred ninety-one".
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