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11411041141 is a prime number
BaseRepresentation
bin10101010000010011…
…01010101101110101
31002110020212221200101
422220021222231311
5141332211304031
65124150114101
7552530151343
oct125011525565
932406787611
1011411041141
114926265115
12226564b931
1310cb133666
147a370a993
1546bbd4361
hex2a826ab75

11411041141 has 2 divisors, whose sum is σ = 11411041142. Its totient is φ = 11411041140.

The previous prime is 11411041111. The next prime is 11411041183. The reversal of 11411041141 is 14114011411.

11411041141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11213751025 + 197290116 = 105895^2 + 14046^2 .

It is a cyclic number.

It is not a de Polignac number, because 11411041141 - 27 = 11411041013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11411041111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705520570 + 5705520571.

It is an arithmetic number, because the mean of its divisors is an integer number (5705520571).

Almost surely, 211411041141 is an apocalyptic number.

It is an amenable number.

11411041141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11411041141 is an equidigital number, since it uses as much as digits as its factorization.

11411041141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 19.

Adding to 11411041141 its reverse (14114011411), we get a palindrome (25525052552).

The spelling of 11411041141 in words is "eleven billion, four hundred eleven million, forty-one thousand, one hundred forty-one".