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11411251122049 is a prime number
BaseRepresentation
bin1010011000001110001110…
…0100011100111110000001
31111101220102201012021020021
42212003203210130332001
52443430220241401144
640134131214213441
72255302304064412
oct246034344347601
944356381167207
1011411251122049
1136aa536849889
1213436b0ab4281
1364a0cba0305c
142b6443ad7809
1514bc75be8884
hexa60e391cf81

11411251122049 has 2 divisors, whose sum is σ = 11411251122050. Its totient is φ = 11411251122048.

The previous prime is 11411251122001. The next prime is 11411251122097. The reversal of 11411251122049 is 94022115211411.

It is a balanced prime because it is at equal distance from previous prime (11411251122001) and next prime (11411251122097).

It can be written as a sum of positive squares in only one way, i.e., 8792055219600 + 2619195902449 = 2965140^2 + 1618393^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11411251122049 is a prime.

It is a super-2 number, since 2×114112511220492 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11411251122449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705625561024 + 5705625561025.

It is an arithmetic number, because the mean of its divisors is an integer number (5705625561025).

Almost surely, 211411251122049 is an apocalyptic number.

It is an amenable number.

11411251122049 is a deficient number, since it is larger than the sum of its proper divisors (1).

11411251122049 is an equidigital number, since it uses as much as digits as its factorization.

11411251122049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 34.

The spelling of 11411251122049 in words is "eleven trillion, four hundred eleven billion, two hundred fifty-one million, one hundred twenty-two thousand, forty-nine".