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114113101 is a prime number
BaseRepresentation
bin1101100110100…
…11101001001101
321221201112202011
412303103221031
5213203104401
615153501221
72553642154
oct663235115
9257645664
10114113101
1159460953
1232271811
131a84555b
141122659b
15a041451
hex6cd3a4d

114113101 has 2 divisors, whose sum is σ = 114113102. Its totient is φ = 114113100.

The previous prime is 114113063. The next prime is 114113113. The reversal of 114113101 is 101311411.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97515625 + 16597476 = 9875^2 + 4074^2 .

It is an emirp because it is prime and its reverse (101311411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114113101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114113171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57056550 + 57056551.

It is an arithmetic number, because the mean of its divisors is an integer number (57056551).

Almost surely, 2114113101 is an apocalyptic number.

It is an amenable number.

114113101 is a deficient number, since it is larger than the sum of its proper divisors (1).

114113101 is an equidigital number, since it uses as much as digits as its factorization.

114113101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

The square root of 114113101 is about 10682.3733786083. The cubic root of 114113101 is about 485.0410579192.

Adding to 114113101 its reverse (101311411), we get a palindrome (215424512).

The spelling of 114113101 in words is "one hundred fourteen million, one hundred thirteen thousand, one hundred one".