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11411410315213 is a prime number
BaseRepresentation
bin1010011000001110110100…
…0011101110011111001101
31111101220211210202010012101
42212003231003232133031
52443431032020041323
640134155102235101
72255306246153416
oct246035503563715
944356753663171
1011411410315213
1136aa60869aa87
121343736285a91
1364a1259a04ac
142b645acd680d
1514bc84b91dad
hexa60ed0ee7cd

11411410315213 has 2 divisors, whose sum is σ = 11411410315214. Its totient is φ = 11411410315212.

The previous prime is 11411410315187. The next prime is 11411410315229. The reversal of 11411410315213 is 31251301411411.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11254267048644 + 157143266569 = 3354738^2 + 396413^2 .

It is an emirp because it is prime and its reverse (31251301411411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11411410315213 - 229 = 11410873444301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11411410312213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705705157606 + 5705705157607.

It is an arithmetic number, because the mean of its divisors is an integer number (5705705157607).

Almost surely, 211411410315213 is an apocalyptic number.

It is an amenable number.

11411410315213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11411410315213 is an equidigital number, since it uses as much as digits as its factorization.

11411410315213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 28.

Adding to 11411410315213 its reverse (31251301411411), we get a palindrome (42662711726624).

The spelling of 11411410315213 in words is "eleven trillion, four hundred eleven billion, four hundred ten million, three hundred fifteen thousand, two hundred thirteen".