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11411419127 is a prime number
BaseRepresentation
bin10101010000010110…
…00110111111110111
31002110021121011011212
422220023012333313
5141332310403002
65124202152035
7552533314343
oct125013067767
932407534155
1011411419127
1149264a30a9
1222657b261b
1310cb236714
147a37a8623
1546bc5b352
hex2a82c6ff7

11411419127 has 2 divisors, whose sum is σ = 11411419128. Its totient is φ = 11411419126.

The previous prime is 11411419087. The next prime is 11411419147. The reversal of 11411419127 is 72191411411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11411419127 - 28 = 11411418871 is a prime.

It is a super-2 number, since 2×114114191272 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11411419093 and 11411419102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11411419147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705709563 + 5705709564.

It is an arithmetic number, because the mean of its divisors is an integer number (5705709564).

Almost surely, 211411419127 is an apocalyptic number.

11411419127 is a deficient number, since it is larger than the sum of its proper divisors (1).

11411419127 is an equidigital number, since it uses as much as digits as its factorization.

11411419127 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2016, while the sum is 32.

The spelling of 11411419127 in words is "eleven billion, four hundred eleven million, four hundred nineteen thousand, one hundred twenty-seven".