11411450233 has 2 divisors, whose sum is σ = 11411450234. Its totient is φ = 11411450232.

The previous prime is 11411450231. The next prime is 11411450291. The reversal of 11411450233 is 33205411411.

11411450233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10109900304 + 1301549929 = 100548^2 + 36077^2 .

It is an emirp because it is prime and its reverse (33205411411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11411450233 - 2¹ = 11411450231 is a prime.

Together with 11411450231, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11411450198 and 11411450207.

It is not a weakly prime, because it can be changed into another prime (11411450231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705725116 + 5705725117.

It is an arithmetic number, because the mean of its divisors is an integer number (5705725117).

Almost surely, 2^11411450233 is an apocalyptic number.

It is an amenable number.

11411450233 is a deficient number, since it is larger than the sum of its proper divisors (1).

11411450233 is an equidigital number, since it uses as much as digits as its factorization.

11411450233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 11411450233 its reverse (33205411411), we get a palindrome (44616861644).

The spelling of 11411450233 in words is "eleven billion, four hundred eleven million, four hundred fifty thousand, two hundred thirty-three".