Base | Representation |
---|---|
bin | 110101001001000010… |
… | …1111010111110110101 |
3 | 101220120020020120200012 |
4 | 1222102011322332311 |
5 | 3332204231104131 |
6 | 124232011230005 |
7 | 11150001326021 |
oct | 1522205727665 |
9 | 356506216605 |
10 | 114120175541 |
11 | 44441955a69 |
12 | 1a14a748305 |
13 | a9b8ca73b8 |
14 | 574849b381 |
15 | 2e7dbaa52b |
hex | 1a9217afb5 |
114120175541 has 2 divisors, whose sum is σ = 114120175542. Its totient is φ = 114120175540.
The previous prime is 114120175531. The next prime is 114120175567. The reversal of 114120175541 is 145571021411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 60936897316 + 53183278225 = 246854^2 + 230615^2 .
It is a cyclic number.
It is not a de Polignac number, because 114120175541 - 214 = 114120159157 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114120175498 and 114120175507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114120175511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57060087770 + 57060087771.
It is an arithmetic number, because the mean of its divisors is an integer number (57060087771).
Almost surely, 2114120175541 is an apocalyptic number.
It is an amenable number.
114120175541 is a deficient number, since it is larger than the sum of its proper divisors (1).
114120175541 is an equidigital number, since it uses as much as digits as its factorization.
114120175541 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5600, while the sum is 32.
Adding to 114120175541 its reverse (145571021411), we get a palindrome (259691196952).
The spelling of 114120175541 in words is "one hundred fourteen billion, one hundred twenty million, one hundred seventy-five thousand, five hundred forty-one".
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