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1141210403 is a prime number
BaseRepresentation
bin100010000000101…
…0111110100100011
32221112101111100222
41010001113310203
54314122213103
6305124033255
740165062014
oct10401276443
92845344328
101141210403
115362022a3
1227a23282b
1315257c438
14ab7c900b
156a2c6638
hex44057d23

1141210403 has 2 divisors, whose sum is σ = 1141210404. Its totient is φ = 1141210402.

The previous prime is 1141210373. The next prime is 1141210417. The reversal of 1141210403 is 3040121411.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1141210403 - 212 = 1141206307 is a prime.

It is a super-2 number, since 2×11412104032 = 2604722367830844818, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1141210423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570605201 + 570605202.

It is an arithmetic number, because the mean of its divisors is an integer number (570605202).

Almost surely, 21141210403 is an apocalyptic number.

1141210403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141210403 is an equidigital number, since it uses as much as digits as its factorization.

1141210403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 1141210403 is about 33781.8057983880. The cubic root of 1141210403 is about 1045.0135153888.

Adding to 1141210403 its reverse (3040121411), we get a palindrome (4181331814).

The spelling of 1141210403 in words is "one billion, one hundred forty-one million, two hundred ten thousand, four hundred three".