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1141212312 = 23321737113223
BaseRepresentation
bin100010000000101…
…1000010010011000
32221112101120222200
41010001120102120
54314122243222
6305124050200
740165100412
oct10401302230
92845346880
101141212312
11536203779
1227a233960
13152580276
14ab7c99b2
156a2c6eac
hex44058498

1141212312 has 192 divisors, whose sum is σ = 3405991680. Its totient is φ = 343719936.

The previous prime is 1141212301. The next prime is 1141212337. The reversal of 1141212312 is 2132121411.

1141212312 is a `hidden beast` number, since 1 + 141 + 212 + 312 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a nude number because it is divisible by every one of its digits.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5117433 + ... + 5117655.

It is an arithmetic number, because the mean of its divisors is an integer number (17739540).

Almost surely, 21141212312 is an apocalyptic number.

1141212312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1141212312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1702995840).

1141212312 is an abundant number, since it is smaller than the sum of its proper divisors (2264779368).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1141212312 is a wasteful number, since it uses less digits than its factorization.

1141212312 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 402 (or 395 counting only the distinct ones).

The product of its digits is 96, while the sum is 18.

The square root of 1141212312 is about 33781.8340532304. The cubic root of 1141212312 is about 1045.0140980829.

Adding to 1141212312 its reverse (2132121411), we get a palindrome (3273333723).

Subtracting 1141212312 from its reverse (2132121411), we obtain a palindrome (990909099).

The spelling of 1141212312 in words is "one billion, one hundred forty-one million, two hundred twelve thousand, three hundred twelve".