Base | Representation |
---|---|
bin | 11001111100101011110101… |
… | …100010000101111110011010 |
3 | 112222001220021121112021221002 |
4 | 121330223311202011332122 |
5 | 104424231112001110020 |
6 | 1042414351513545002 |
7 | 33015666455136260 |
oct | 3174536542057632 |
9 | 488056247467832 |
10 | 114121400410010 |
11 | 333a9683435724 |
12 | 109715aa115162 |
13 | 4b8a7a9447516 |
14 | 20277105a4430 |
15 | d2d85d599975 |
hex | 67caf5885f9a |
114121400410010 has 64 divisors (see below), whose sum is σ = 248900314959360. Its totient is φ = 36777337681920.
The previous prime is 114121400410009. The next prime is 114121400410091. The reversal of 114121400410010 is 10014004121411.
It is a super-2 number, since 2×1141214004100102 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 62103830 + ... + 63915009.
It is an arithmetic number, because the mean of its divisors is an integer number (3889067421240).
Almost surely, 2114121400410010 is an apocalyptic number.
114121400410010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
114121400410010 is an abundant number, since it is smaller than the sum of its proper divisors (134778914549350).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114121400410010 is a wasteful number, since it uses less digits than its factorization.
114121400410010 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 126019631.
The product of its (nonzero) digits is 128, while the sum is 20.
Adding to 114121400410010 its reverse (10014004121411), we get a palindrome (124135404531421).
The spelling of 114121400410010 in words is "one hundred fourteen trillion, one hundred twenty-one billion, four hundred million, four hundred ten thousand, ten".
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