Base | Representation |
---|---|
bin | 110101001001000111… |
… | …0100010001001001100 |
3 | 101220120101111021110111 |
4 | 1222102032202021030 |
5 | 3332210320324400 |
6 | 124232131445404 |
7 | 11150026450564 |
oct | 1522216421114 |
9 | 356511437414 |
10 | 114122433100 |
11 | 44443158115 |
12 | 1a14b456864 |
13 | a9b95b7b30 |
14 | 57488c7da4 |
15 | 2e7dea43ba |
hex | 1a923a224c |
114122433100 has 72 divisors (see below), whose sum is σ = 282383363808. Its totient is φ = 39658828800.
The previous prime is 114122432993. The next prime is 114122433107. The reversal of 114122433100 is 1334221411.
It is a super-2 number, since 2×1141224331002 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (114122433107) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2559856 + ... + 2604055.
It is an arithmetic number, because the mean of its divisors is an integer number (3921991164).
Almost surely, 2114122433100 is an apocalyptic number.
114122433100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
114122433100 is an abundant number, since it is smaller than the sum of its proper divisors (168260930708).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114122433100 is a wasteful number, since it uses less digits than its factorization.
114122433100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5163955 (or 5163948 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 114122433100 its reverse (1334221411), we get a palindrome (115456654511).
The spelling of 114122433100 in words is "one hundred fourteen billion, one hundred twenty-two million, four hundred thirty-three thousand, one hundred".
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