Base | Representation |
---|---|
bin | 11001111100101101101001… |
… | …101111100101001000010111 |
3 | 112222002002022111012221021221 |
4 | 121330231221233211020113 |
5 | 104424244110111240201 |
6 | 1042415313202351211 |
7 | 33016066001223136 |
oct | 3174555157451027 |
9 | 488062274187257 |
10 | 114123350102551 |
11 | 333aa493a41579 |
12 | 10971a5305b507 |
13 | 4b8aa2a35954a |
14 | 20278574c591d |
15 | d2d9248214a1 |
hex | 67cb69be5217 |
114123350102551 has 2 divisors, whose sum is σ = 114123350102552. Its totient is φ = 114123350102550.
The previous prime is 114123350102539. The next prime is 114123350102603. The reversal of 114123350102551 is 155201053321411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114123350102551 - 211 = 114123350100503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114123300102551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57061675051275 + 57061675051276.
It is an arithmetic number, because the mean of its divisors is an integer number (57061675051276).
Almost surely, 2114123350102551 is an apocalyptic number.
114123350102551 is a deficient number, since it is larger than the sum of its proper divisors (1).
114123350102551 is an equidigital number, since it uses as much as digits as its factorization.
114123350102551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 34.
The spelling of 114123350102551 in words is "one hundred fourteen trillion, one hundred twenty-three billion, three hundred fifty million, one hundred two thousand, five hundred fifty-one".
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