Base | Representation |
---|---|
bin | 10101010000011101… |
… | …10110011111100111 |
3 | 1002110100102222211022 |
4 | 22220032312133213 |
5 | 141333033300403 |
6 | 5124235201355 |
7 | 552544541336 |
oct | 125016663747 |
9 | 32410388738 |
10 | 11412400103 |
11 | 4927003125 |
12 | 2265ba625b |
13 | 10cb4bb090 |
14 | 7a3981d1d |
15 | 46bda1d38 |
hex | 2a83b67e7 |
11412400103 has 32 divisors (see below), whose sum is σ = 13115880960. Its totient is φ = 9843016320.
The previous prime is 11412400099. The next prime is 11412400121. The reversal of 11412400103 is 30100421411.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 11412400103 - 22 = 11412400099 is a prime.
It is a super-2 number, since 2×114124001032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11412400303) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7453448 + ... + 7454978.
It is an arithmetic number, because the mean of its divisors is an integer number (409871280).
Almost surely, 211412400103 is an apocalyptic number.
11412400103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11412400103 is a deficient number, since it is larger than the sum of its proper divisors (1703480857).
11412400103 is a wasteful number, since it uses less digits than its factorization.
11412400103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1959.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 11412400103 its reverse (30100421411), we get a palindrome (41512821514).
The spelling of 11412400103 in words is "eleven billion, four hundred twelve million, four hundred thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •