Base | Representation |
---|---|
bin | 110101001001010110… |
… | …0001010101011101000 |
3 | 101220120221002221110100 |
4 | 1222102230022223220 |
5 | 3332214312420240 |
6 | 124233010145400 |
7 | 11150152463502 |
oct | 1522254125350 |
9 | 356527087410 |
10 | 114130201320 |
11 | 44447583533 |
12 | 1a151b82260 |
13 | a9bb0a7905 |
14 | 574994ad72 |
15 | 2e7e9dae30 |
hex | 1a92b0aae8 |
114130201320 has 48 divisors (see below), whose sum is σ = 370923155460. Its totient is φ = 30434720256.
The previous prime is 114130201313. The next prime is 114130201351. The reversal of 114130201320 is 23102031411.
114130201320 is a `hidden beast` number, since 1 + 1 + 41 + 302 + 0 + 1 + 320 = 666.
114130201320 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 114031834596 + 98366724 = 337686^2 + 9918^2 .
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 114130201293 and 114130201302.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 158513809 + ... + 158514528.
Almost surely, 2114130201320 is an apocalyptic number.
114130201320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
114130201320 is an abundant number, since it is smaller than the sum of its proper divisors (256792954140).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114130201320 is a wasteful number, since it uses less digits than its factorization.
114130201320 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 317028354 (or 317028347 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 114130201320 its reverse (23102031411), we get a palindrome (137232232731).
The spelling of 114130201320 in words is "one hundred fourteen billion, one hundred thirty million, two hundred one thousand, three hundred twenty".
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