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114131203100 = 22521141312031
BaseRepresentation
bin110101001001010111…
…1111111010000011100
3101220120222222211122022
41222102233333100130
53332220041444400
6124233043435312
711150164135235
oct1522257772034
9356528884568
10114131203100
11444480a8152
121a152385b38
13a9bb368895
145749b2c08c
152e7eb37b85
hex1a92bff41c

114131203100 has 18 divisors (see below), whose sum is σ = 247664710944. Its totient is φ = 45652481200.

The previous prime is 114131203079. The next prime is 114131203127. The reversal of 114131203100 is 1302131411.

It is a super-2 number, since 2×1141312031002 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 570655916 + ... + 570656115.

It is an arithmetic number, because the mean of its divisors is an integer number (13759150608).

Almost surely, 2114131203100 is an apocalyptic number.

114131203100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

114131203100 is an abundant number, since it is smaller than the sum of its proper divisors (133533507844).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

114131203100 is a wasteful number, since it uses less digits than its factorization.

114131203100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1141312045 (or 1141312038 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 114131203100 its reverse (1302131411), we get a palindrome (115433334511).

The spelling of 114131203100 in words is "one hundred fourteen billion, one hundred thirty-one million, two hundred three thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 1141312031 2282624062 4565248124 5706560155 11413120310 22826240620 28532800775 57065601550 114131203100