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11413214143 is a prime number
BaseRepresentation
bin10101010000100011…
…11101001110111111
31002110101222100110221
422220101331032333
5141333240323033
65124304442211
7552554501542
oct125021751677
932411870427
1011413214143
114927509791
122266319367
1310cb714766
147a3b14859
1546beb312d
hex2a847d3bf

11413214143 has 2 divisors, whose sum is σ = 11413214144. Its totient is φ = 11413214142.

The previous prime is 11413214117. The next prime is 11413214147. The reversal of 11413214143 is 34141231411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11413214143 - 233 = 2823279551 is a prime.

It is a super-2 number, since 2×114132141432 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11413214147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706607071 + 5706607072.

It is an arithmetic number, because the mean of its divisors is an integer number (5706607072).

Almost surely, 211413214143 is an apocalyptic number.

11413214143 is a deficient number, since it is larger than the sum of its proper divisors (1).

11413214143 is an equidigital number, since it uses as much as digits as its factorization.

11413214143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 25.

Adding to 11413214143 its reverse (34141231411), we get a palindrome (45554445554).

The spelling of 11413214143 in words is "eleven billion, four hundred thirteen million, two hundred fourteen thousand, one hundred forty-three".