Base | Representation |
---|---|
bin | 10101010000100011… |
… | …11101001110111111 |
3 | 1002110101222100110221 |
4 | 22220101331032333 |
5 | 141333240323033 |
6 | 5124304442211 |
7 | 552554501542 |
oct | 125021751677 |
9 | 32411870427 |
10 | 11413214143 |
11 | 4927509791 |
12 | 2266319367 |
13 | 10cb714766 |
14 | 7a3b14859 |
15 | 46beb312d |
hex | 2a847d3bf |
11413214143 has 2 divisors, whose sum is σ = 11413214144. Its totient is φ = 11413214142.
The previous prime is 11413214117. The next prime is 11413214147. The reversal of 11413214143 is 34141231411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11413214143 - 233 = 2823279551 is a prime.
It is a super-2 number, since 2×114132141432 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11413214147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706607071 + 5706607072.
It is an arithmetic number, because the mean of its divisors is an integer number (5706607072).
Almost surely, 211413214143 is an apocalyptic number.
11413214143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11413214143 is an equidigital number, since it uses as much as digits as its factorization.
11413214143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1152, while the sum is 25.
Adding to 11413214143 its reverse (34141231411), we get a palindrome (45554445554).
The spelling of 11413214143 in words is "eleven billion, four hundred thirteen million, two hundred fourteen thousand, one hundred forty-three".
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