Base | Representation |
---|---|
bin | 10000100110111100001… |
… | …010100010010110011111 |
3 | 11001002221202222110010011 |
4 | 100212330022202112133 |
5 | 122144412220242231 |
6 | 2232152221224051 |
7 | 145313024143561 |
oct | 20467412422637 |
9 | 4032852873104 |
10 | 1141323212191 |
11 | 40003a220a28 |
12 | 165242a02027 |
13 | 8381b032016 |
14 | 3d3516b9331 |
15 | 1ea4d7109b1 |
hex | 109bc2a259f |
1141323212191 has 2 divisors, whose sum is σ = 1141323212192. Its totient is φ = 1141323212190.
The previous prime is 1141323212171. The next prime is 1141323212233. The reversal of 1141323212191 is 1912123231411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1141323212191 is a prime.
It is a super-2 number, since 2×11413232121912 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1141323212171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570661606095 + 570661606096.
It is an arithmetic number, because the mean of its divisors is an integer number (570661606096).
Almost surely, 21141323212191 is an apocalyptic number.
1141323212191 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141323212191 is an equidigital number, since it uses as much as digits as its factorization.
1141323212191 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592, while the sum is 31.
The spelling of 1141323212191 in words is "one trillion, one hundred forty-one billion, three hundred twenty-three million, two hundred twelve thousand, one hundred ninety-one".
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