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114132602434142 = 21723145949619481
BaseRepresentation
bin11001111100110110010001…
…001110011011001001011110
3112222002222012022010002011202
4121330312101032123021132
5104424422032210343032
61042423443240115502
733016544166566615
oct3174662116331136
9488088168102152
10114132602434142
1133403401709206
12109737b5765b92
134b8b873187576
14202809422287c
15d2dcb6c42d62
hex67cd9139b25e

114132602434142 has 16 divisors (see below), whose sum is σ = 189150706848672. Its totient is φ = 51374266056960.

The previous prime is 114132602434129. The next prime is 114132602434153. The reversal of 114132602434142 is 241434206231411.

It is a junction number, because it is equal to n+sod(n) for n = 114132602434096 and 114132602434105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 72974808959 + ... + 72974810522.

It is an arithmetic number, because the mean of its divisors is an integer number (11821919178042).

Almost surely, 2114132602434142 is an apocalyptic number.

114132602434142 is a deficient number, since it is larger than the sum of its proper divisors (75018104414530).

114132602434142 is a wasteful number, since it uses less digits than its factorization.

114132602434142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 145949619523.

The product of its (nonzero) digits is 110592, while the sum is 38.

Adding to 114132602434142 its reverse (241434206231411), we get a palindrome (355566808665553).

The spelling of 114132602434142 in words is "one hundred fourteen trillion, one hundred thirty-two billion, six hundred two million, four hundred thirty-four thousand, one hundred forty-two".

Divisors: 1 2 17 23 34 46 391 782 145949619481 291899238962 2481143531177 3356841248063 4962287062354 6713682496126 57066301217071 114132602434142